12x^2+60x=15

Solution for 12x^2+60x=15 equation:

12x^2+60x=15

We move all terms to the left:

12x^2+60x-(15)=0

a = 12; b = 60; c = -15;
Δ = b2-4ac
Δ = 602-4·12·(-15)
Δ = 4320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4320}=\sqrt{144*30}=\sqrt{144}*\sqrt{30}=12\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{30}}{2*12}=\frac{-60-12\sqrt{30}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{30}}{2*12}=\frac{-60+12\sqrt{30}}{24}
$